alleryStart learning →The sum of the first 10 natural numbers (1, 2, 3, …, 10) is:
- 100
- 45
- 55
- 50
Show answer and solution
Correct answer: C. 55
We have S₁₀ = 10/2 (1+10).
That is S₁₀ = 5×11.
So S₁₀ = 55.
Indian Navy Pilot Arithmetic Progressions — practice questions
Explore 6 free Arithmetic Progressions questions in Indian Navy Pilot Mathematics. Open each question or exercise to read its content, reference answers and available explanation.
Practise Arithmetic Progressions with Quill →Arithmetic Progressions questions and exercises with answers
Showing questions 1–6 of 6.
The sum of the first 10 natural numbers (1, 2, 3, …, 10) is:Read the answer and worked solution →Find the common difference of the AP 7, 11, 15, 19, …Read the answer and worked solution →Sum the AP 2 + 4 + 6 + … + 100.Read the answer and worked solution →How many three-digit numbers are divisible by 7?Read the answer and worked solution →Match each AP termRead the answer and worked solution →Key in the AP answerRead the answer and worked solution →
Worked practice questions
Find the common difference of the AP 7, 11, 15, 19, …
- 5
- 3
- 4
- 11
Show answer and solution
Correct answer: C. 4
d = 11 − 7 = 4. Verify with the next pair: 15 − 11 = 4.
Sum the AP 2 + 4 + 6 + … + 100.
- 2550
- 2500
- 2600
- 5050
Show answer and solution
Correct answer: A. 2550
First term 2, last term 100, d = 2. Number of terms: n = (100 − 2)/2 + 1 = 50. Sum: 50/2 (2 + 100) = 25 × 102 = 2550.
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