The **slope of the tangent** to the curve $y = f(x)$ at point $(a, f(a))$ is:
- $f(a)$
- $f'(a)$
- $1/f'(a)$
- $f''(a)$
Show answer and solution
Correct answer: B. $f'(a)$
Tangent slope at $x = a$ equals $f'(a)$, the derivative evaluated at that point.
Normal slope = $-1/f'(a)$ (perpendicular).