PA and PB are tangents from a point P to a circle. If angle APB = 90 degrees, the radius and PA are related by
- PA = r
- PA = r (square root of 2)
- PA = 2 r
- PA = r/2
Show answer and solution
Correct answer: A. PA = r
1. In quadrilateral OAPB, all four angles: OAP = OBP = 90, APB = 90, AOB = 90.
2. OAPB is a square with side r and side PA.
3. Hence PA = r.
_Source: syllabus Mathematics, Ch 10 "Circles", §10.3_