For Newton's law of cooling, body at 80°C cools in room at 20°C. After time, T = 60°C. Find k if time = 5 min:
- k = ln 60
- k = 1
- k = (1/5) ln(3/2) ≈ 0.081 min⁻¹
- k = 0
Show answer and solution
Correct answer: C. k = (1/5) ln(3/2) ≈ 0.081 min⁻¹
T - T_env = (T₀ - T_env) e^(-kt).
60 - 20 = 60 e^(-5k)
We have → 40 = 60 e^(-5k) → e^(-5k).
So → 40 = 2/3.
We have → -5k = ln(2/3) → k.
So → -5k = (1/5) ln(3/2) ≈ 0.081.