Two tangents PA and PB are drawn from an external point P to a circle. If angle APB = 60 degrees, then angle AOB equals
- 60 degrees
- 90 degrees
- 150 degrees
- 120 degrees
Show answer and solution
Correct answer: D. 120 degrees
1. In quadrilateral OAPB, angles OAP and OBP are both 90 degrees (tangent perpendicular to radius).
2. Sum of all four angles = 360 degrees, so AOB + APB = 180.
3. AOB = 180 - 60 = 120 degrees.
_Source: syllabus Mathematics, Ch 10 "Circles", §10.3_