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Indian Navy 10+2 B.Tech Cadet Atoms and Nuclei — practice questions

Explore 3 free Atoms and Nuclei questions in Indian Navy 10+2 B.Tech Cadet Physics. Open each question or exercise to read its content, reference answers and available explanation.

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Atoms and Nuclei questions and exercises with answers

Showing questions 1–3 of 3.

Worked practice questions

Lyman series transitions land at n = ___, lying in:

  1. n = 1, ULTRAVIOLET
  2. n = 2, visible
  3. n = 3, infrared
  4. n = 4, radio
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Correct answer: A. n = 1, ULTRAVIOLET

**Lyman:** transitions to n = 1 (UV). **Balmer:** to n = 2 (visible, includes Hα = 656 nm). Paschen: to n = 3 (IR). **Brackett:** to n = 4 (far IR). Pfund: to n = 5.

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Activity of 1 gram of ²²⁶Ra (Avogadro = 6 × 10²³; T₁/₂ = 1600 yr):

  1. 10²³ Bq
  2. 10⁵ Bq
  3. Cannot determine
  4. ≈ 3.7 × 10¹⁰ Bq (1 Ci, by definition)
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Correct answer: D. ≈ 3.7 × 10¹⁰ Bq (1 Ci, by definition)

N = (1 g / 226 g/mol) × 6 × 10²³ ≈ 2.66 × 10²¹ atoms. λ = 0.693 / (1600 × 365.25 × 86400) ≈ 1.37 × 10⁻¹¹ /s. A = λN ≈ 3.65 × 10¹⁰ Bq ≈ 1 Ci. (Original definition of curie.)

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Order the steps of EM wave generation by an accelerating charge

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Steps
  1. Charge accelerates, creating a changing electric field
  2. Changing E-field induces a changing magnetic field
  3. Changing B-field induces a changing E-field further away
  4. The coupled E and B fields propagate outward as a wave
  5. Wave travels in vacuum at c = 3×10⁸ m/s

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