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Indian Navy 10+2 B.Tech Cadet Probability — practice questions — page 2

Explore 35 free Probability questions in Indian Navy 10+2 B.Tech Cadet Mathematics. Open each question or exercise to read its content, reference answers and available explanation.

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Probability questions and exercises with answers

Showing questions 31–35 of 35.

Tap every quantity that is a probabilityRead the answer and worked solution →Spot the odd one outRead the answer and worked solution →Assertion and reason: the multiplication ruleRead the answer and worked solution →True or false: the Historical NoteRead the answer and worked solution →Sort each statement by which idea it describesRead the answer and worked solution →

Worked practice questions

Tap every quantity that is a probability

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Questions
  1. Items
    1. Text
      P(E|F)
      Matches the category
      Yes
    2. Text
      P(E ∩ F)
      Matches the category
      Yes
    3. Text
      P(A)
      Matches the category
      Yes
    4. Text
      E′
      Matches the category
      No
    5. Text
      S
      Matches the category
      No
    Category
    Is a probability (a number in [0, 1])
Keeping the objects straight: some symbols name events, others name numbers. Source: syllabus Maths Part II, Ch 13 Probability.

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Spot the odd one out

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Questions
  1. Items
    1. P(E)P(F|E)
    2. P(E) + P(F)
    3. P(F)P(E|F)
    Odd item
    P(E) + P(F)
  2. Items
    1. Prior
    2. Cofactor
    3. Posterior
    4. Partition
    Odd item
    Cofactor
  3. Items
    1. Pairwise disjoint
    2. Union equals S
    3. All equally likely
    4. Nonzero probability
    Odd item
    All equally likely
Each group is one bullet of the summary. Source: syllabus Maths Part II, Ch 13 Probability.

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Assertion and reason: the multiplication rule

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Questions
  1. Reason
    You may condition on either event, provided its probability is nonzero.
    Verdict
    Both are true; the reason explains the assertion.
    Assertion
    P(E ∩ F) can be written two different ways.
  2. Reason
    Independence makes P(F|E) equal to P(F).
    Verdict
    Both are true; the reason explains the assertion.
    Assertion
    For independent events the multiplication rule simplifies.
  3. Reason
    Bayes' theorem has a sum in its denominator.
    Verdict
    Both are true; the reason does not explain the assertion.
    Assertion
    Conditional probability lies between 0 and 1.
Both halves true does not mean one explains the other. Source: syllabus Maths Part II, Ch 13 Probability.

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