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ICSE Class 10 Principles of Inheritance and Variation — practice questions — page 2

Explore 55 free Principles of Inheritance and Variation questions in ICSE Class 10 Biology. Open each question or exercise to read its content, reference answers and available explanation.

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Principles of Inheritance and Variation questions and exercises with answers

Showing questions 31–55 of 55.

T is dominant to t. A tall pea crossed with tt yields a dwarf. The tall pea is:Read the answer and worked solution →A tall pea × tt gives eight tall offspring. With T dominant, TT is:Read the answer and worked solution →With tallness dominant, which tall pea can produce dwarfs on selfing?Read the answer and worked solution →An F2 has the Mendelian 9:3:3:1 ratio. What fraction shows both dominant traits?Read the answer and worked solution →For a 9:3:3:1 F2, add the classes expressing just one dominant trait.Read the answer and worked solution →In a 9:3:3:1 F2, the double-recessive class is expected to be:Read the answer and worked solution →A dihybrid F2 fits 9:3:3:1. Why need a sample of 16 not match it exactly?Read the answer and worked solution →Classical X-recessive haemophilia: carrier mother, unaffected father. Risk per son?Read the answer and worked solution →For X-linked haemophilia, why does an affected father not give his allele to sons?Read the answer and worked solution →Classical X-recessive haemophilia: affected mother, normal father. A son's risk?Read the answer and worked solution →A carrier woman and affected man have a daughter. In classical X-recessive haemophilia, risk?Read the answer and worked solution →A carrier's daughter has a normal father. In classical X-recessive red-green blindness, risk?Read the answer and worked solution →X-recessive red-green blindness: an affected son gets the relevant X allele from:Read the answer and worked solution →Haemophilia affects a protein involved mainly in which process?Read the answer and worked solution →In the usual human XX/XY model, an ovum carries which sex chromosome?Read the answer and worked solution →In the usual human XX/XY model, which fertilisation produces an XY zygote?Read the answer and worked solution →Assume equal, independent XX/XY outcomes. After two sons, the next child's XY chance is:Read the answer and worked solution →Which observation is an example of variation within one species?Read the answer and worked solution →Why may offspring produced asexually still differ slightly from their parent?Read the answer and worked solution →Sexual reproduction increases genetic variety chiefly by:Read the answer and worked solution →Which change is a mutation?Read the answer and worked solution →A pea is genetically Tt but is observed to be tall. Which label describes Tt?Read the answer and worked solution →Mendel's pea flowers had which contrasting positions?Read the answer and worked solution →Which pair describes the pea pod colours Mendel studied?Read the answer and worked solution →Mendel contrasted violet pea flowers with flowers of which colour?Read the answer and worked solution →

Worked practice questions

T is dominant to t. A tall pea crossed with tt yields a dwarf. The tall pea is:

  1. Homozygous dominant
  2. Either homozygous type
  3. A heterozygous type
  4. Homozygous recessive
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Correct answer: C. A heterozygous type

Producing a tt offspring proves that the tall parent supplied t.

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A tall pea × tt gives eight tall offspring. With T dominant, TT is:

  1. Ruled out by the cross
  2. Certain from this sample
  3. Possible but not proven
  4. Impossible in this trait
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Correct answer: C. Possible but not proven

A Tt parent can by chance produce eight tall offspring with a tt tester.

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With tallness dominant, which tall pea can produce dwarfs on selfing?

  1. Neither tall genotype
  2. Only homozygous tall
  3. Both tall genotypes
  4. Only heterozygous tall
Show answer and solution

Correct answer: D. Only heterozygous tall

Selfing Tt can unite two t gametes to produce tt offspring.

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