By partial fractions, ∫ dx/(x(x+1)) equals:
- ln |x| + C
- ln |x(x+1)| + C
- ln |x/(x+1)| + C
- arctan x + C
Show answer and solution
Correct answer: C. ln |x/(x+1)| + C
1/(x(x+1)) = 1/x - 1/(x+1).
We have ∫ = ln |x| - ln |x+1| + C.
So ∫ = ln |x/(x+1)| + C.