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DSSSB TGT Motion — practice questions

Explore 3 free Motion questions in DSSSB TGT Science. Open each question or exercise to read its content, reference answers and available explanation.

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Motion questions and exercises with answers

Showing questions 1–3 of 3.

A cab covers 60 km in 1.5 hours. Its AVERAGE SPEED is:Read the answer and worked solution →A car accelerates from 10 m/s to 20 m/s in 5 seconds. Its acceleration is:Read the answer and worked solution →A train starts from rest (u = 0) and accelerates uniformly at a = 2 m/s² for t = 10 s. The distance it covers is:Read the answer and worked solution →

Worked practice questions

A cab covers 60 km in 1.5 hours. Its AVERAGE SPEED is:

  1. 60 km/h, equal to the distance numerically
  2. 40 km/h, equal to distance divided by time
  3. 90 km/h, equal to distance times the time
  4. 30 km/h, equal to half the actual distance
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Correct answer: B. 40 km/h, equal to distance divided by time

Average speed = total distance / total time = 60 / 1.5 = 40 km/h.

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A car accelerates from 10 m/s to 20 m/s in 5 seconds. Its acceleration is:

  1. 2 m/s², because (20-10)/5
  2. 6 m/s², because (10+20)/5
  3. 10 m/s², because the full velocity change
  4. 0.5 m/s², because 1 over (20-10)
Show answer and solution

Correct answer: A. 2 m/s², because (20-10)/5

Acceleration = (v - u) / t = (20 - 10) / 5 = 2 m/s².

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A train starts from rest (u = 0) and accelerates uniformly at a = 2 m/s² for t = 10 s. The distance it covers is:

  1. 20 m, using s = ut + ½at² with u = 0
  2. 100 m, using s = ½at² for u = 0 case
  3. 200 m, using s = ½at² with t squared as 100
  4. 50 m, using s = (a × t) / 2 incorrectly
Show answer and solution

Correct answer: B. 100 m, using s = ½at² for u = 0 case

From rest (u = 0), s = ½at² = ½ × 2 × 10² = ½ × 2 × 100 = 100 m.

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How to practise

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