DSSSB TGT motion — practice questions
31 free MCQs with worked solutions. Tap any question for the answer + explanation, or practice them all in the app.
Practice DSSSB TGT motion in the app →Motion in a straight line is also called:The shortest straight-line distance from the starting point to the final position is called:The SI unit of speed is:A car travels 50 km north and then 30 km south. The DISPLACEMENT is:An athlete runs once around a circular track of perimeter 400 m and returns to the start in 50 seconds. Her avA car uniformly accelerates from rest to 20 m/s in 10 seconds. Its acceleration is:A car decelerates uniformly from 30 m/s to 0 in 6 seconds. Its acceleration is:A ball is thrown vertically upward and returns to its starting point. The total displacement and total distancFor an object moving in a straight line with positive velocity and positive acceleration, the object is:A bus starts from rest and accelerates at 2 m/s² for 10 s. The distance it travels in this time is:Two cars start from rest and accelerate uniformly. Car A reaches 20 m/s in 5 s. Car B reaches 30 m/s in 10 s. The slope of a DISTANCE-TIME graph represents the:On a velocity-time graph, the slope represents the:The first equation of motion is:A bus travelling at 10 m/s accelerates uniformly at 2 m/s² for 5 seconds. Its final velocity is:A car starts from rest and reaches 30 m/s in 6 seconds. The distance covered in this time is:The figure shows a velocity-time graph for an object.
. The TIME to reach the highest point is:Using v² = u² + 2as, find the distance a car needs to stop from 20 m/s if its deceleration is 4 m/s²:A car covers the first half of its journey at 60 km/h and the second half at 40 km/h. The AVERAGE speed for thTwo cars A and B move along straight lines. Their position-time graphs are shown.
![Position-time graph of twAt what time, t, will an object thrown vertically upward at 30 m/s reach its maximum height? (Take g = 10 m/s²An object's velocity-time graph is a straight HORIZONTAL line at v = 5 m/s for 10 seconds. The distance travelA student runs once around a circular school playground of perimeter 400 metres and returns to the starting poA cab covers 60 km in 1.5 hours. Its AVERAGE SPEED is:A car accelerates from 10 m/s to 20 m/s in 5 seconds. Its acceleration is:A car starting at u = 5 m/s accelerates uniformly at a = 2 m/s² for t = 4 s. Its final velocity v is:A train starts from rest (u = 0) and accelerates uniformly at a = 2 m/s² for t = 10 s. The distance it covers A car braking uniformly decelerates from 20 m/s to rest with deceleration 5 m/s². The braking distance is:In a distance-time graph, a STRAIGHT HORIZONTAL line means:In a velocity-time graph, the AREA UNDER the curve gives: