alleryStart learning →What is the minor axis length of the ellipse 9x² + 4y² = 36?
- 4
- 2
- 3
- 6
Show answer and solution
Correct answer: A. 4
Dividing by 36 gives x²/4 + y²/9 = 1, so the semi-minor axis is 2 and the minor axis is 4.
CBSE Class 11 (Commerce) Conic Sections — practice questions — page 4
Explore 100 free Conic Sections questions in CBSE Class 11 (Commerce) Mathematics. Open each question or exercise to read its content, reference answers and available explanation.
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What is the minor axis length of the ellipse 9x² + 4y² = 36?Read the answer and worked solution →The latus rectum of an ellipse with semi-axes a and b has lengthRead the answer and worked solution →An ellipse has vertices (±13, 0) and foci (±5, 0). Its equation isRead the answer and worked solution →An ellipse has semi-major axis 13 and semi-minor axis 12. How far apart are its foci?Read the answer and worked solution →The constant sum of focal distances on an ellipse is always what compared to the distance between the foci?Read the answer and worked solution →A non-degenerate conic with eccentricity exactly 1 is aRead the answer and worked solution →Eccentricity of an ellipse measures how far the ellipse deviates from beingRead the answer and worked solution →How many branches does a hyperbola have?Read the answer and worked solution →A hyperbola is the locus of points where which quantity for two foci is constant?Read the answer and worked solution →The parabola y² = 4ax with a > 0 extends indefinitely into which quadrants?Read the answer and worked solution →
Worked practice questions
The latus rectum of an ellipse with semi-axes a and b has length
- 2a²/b
- 2b/a
- 2b²/a
- b²/a
Show answer and solution
Correct answer: C. 2b²/a
Taking the focus at (c, 0), the ordinate on the ellipse is b²/a, so the full chord is 2b²/a.
An ellipse has vertices (±13, 0) and foci (±5, 0). Its equation is
- x²/169 + y²/144 = 1
- x²/169 + y²/25 = 1
- x²/144 + y²/169 = 1
- x²/13 + y²/5 = 1
Show answer and solution
Correct answer: A. x²/169 + y²/144 = 1
With a = 13 and c = 5, b² = 169 - 25 = 144, so x²/169 + y²/144 = 1.
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