The integrating factor for the linear DE $\dfrac{dy}{dx} + P(x)y = Q(x)$ is:
- $\int P\,dx$
- $e^{\int P\,dx}$
- $e^{-\int P\,dx}$
- $e^{Q}$
Show answer and solution
Correct answer: B. $e^{\int P\,dx}$
Multiplying by $\mu = e^{\int P\,dx}$ turns the LHS into $\dfrac{d}{dx}(\mu y)$.
**Then integrate both sides:** $\mu y = \int Q\mu\,dx + c$.