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Bihar Board Class 10 (BSEB) Physics — practice by topic

Browse 129 questions across 18 Physics topics. Choose what you want to revise, then open a question to check its answer and worked solution.

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Physics topics

The Human Eye and the Colourful World (31)Electricity (26)Sources of Energy (23)Magnetic Effects of Electric Current (22)Light - Reflection and Refraction (9)C10lensformula (6)C10mirrorformula (5)C10refractionlenses (5)C10magneticeffects (2)C9kineticenergy (2)Current Affairs (2)Force (2)Laws of Motion (2)Physics and Measurement (2)Work and Energy (2)Workenergy (2)C10reflectionmirrors (1)Light (1)

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As per your syllabus, what is FOCAL LENGTH (f) of a spherical mirror?Read the answer and worked solution →As per your syllabus, what is the MIRROR FORMULA — relating object distance (u), image distance (v), and focal length (f)?Read the answer and worked solution →As per your syllabus, a NEGATIVE value of magnification m for a mirror indicates what?Read the answer and worked solution →As per your syllabus, if the radius of curvature of a spherical mirror is 20 cm, what is its focal length?Read the answer and worked solution →

Worked practice questions

As per your syllabus, what is FOCAL LENGTH (f) of a spherical mirror?

  1. Half the aperture
  2. Twice the radius of curvature
  3. The distance between the POLE (P) and the PRINCIPAL FOCUS (F)
  4. Distance from pole to centre of curvature
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Correct answer: C. The distance between the POLE (P) and the PRINCIPAL FOCUS (F)

As per your syllabus, f = distance PF. R = 2f relates focal length to radius of curvature.

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As per your syllabus, what is the MIRROR FORMULA — relating object distance (u), image distance (v), and focal length (f)?

  1. 1/v + 1/u = 1/f
  2. 1/v × 1/u = 1/f
  3. v + u = f
  4. 1/v − 1/u = 1/f (this is the lens formula)
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Correct answer: A. 1/v + 1/u = 1/f

As per your syllabus, Eq 9.1, mirror formula = 1/v + 1/u = 1/f. The lens formula is 1/v − 1/u = 1/f (different sign).

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As per your syllabus, a NEGATIVE value of magnification m for a mirror indicates what?

  1. The image is virtual (erect)
  2. The image is at infinity
  3. The image is REAL (inverted)
  4. The image is point-sized
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Correct answer: C. The image is REAL (inverted)

As per your syllabus, §Magnification, negative m = real (inverted) image. Positive m = virtual (erect) image.

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