alleryStart learning →$\int_0^1 \dfrac{dx}{1+x^2}$ equals:
- $\pi/2$
- $\pi/4$
- $\pi/3$
- $1$
Show answer and solution
Correct answer: B. $\pi/4$
$\int_0^1 dx/(1+x^2) = [\tan^{-1}x]_0^1 = \tan^{-1}1 - \tan^{-1}0 = \pi/4 - 0 = \pi/4$.
Assam CEE Standard Integrals — practice questions
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