A fair coin is tossed 10 times. The probability of getting **exactly 6 heads** is:
- $105/512$
- $210/1024$
- Both A and B (same fraction)
- $1/2$
Show answer and solution
Correct answer: C. Both A and B (same fraction)
$P(X = 6) = {}^{10}C_6 (1/2)^{10} = 210 \cdot 1/1024 = 210/1024 = 105/512$.
Both answers represent the same value.