AP Intermediate 2nd Year Classification of Elements and Periodicity in Properties — practice questions

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Glucose in open-chain form has a:Read the answer and worked solution →

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Glucose in open-chain form has a:

Ketone group at C-2, like fructose has in the same molecule
Aldehyde group at C-1, with four chiral carbons in the chain
Carboxylic acid group at C-1, with five hydroxyl groups
Ester group at C-6, with a cyclic structure in solid form

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Correct answer: B. Aldehyde group at C-1, with four chiral carbons in the chain

Glucose open chain: aldehyde at C-1 and -OH at C-2 to C-5 with -CH$_2$OH at C-6; four chiral C.

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