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AIIMS UG Optics — practice questions

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Optics questions and exercises with answers

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A galvanometer of resistance G can be converted into a voltmeter of range V by connecting in series a high resistance R given by:

  1. R = G + V
  2. R = V / I_g − G
  3. R = G I_g / V
  4. R = V · G
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Correct answer: B. R = V / I_g − G

1. Galvanometer gives full deflection at current I_g, so V_g = I_g G. 2. To make it read up to V, drop the excess (V − V_g) across an added series R. 3. At full deflection I_g flows through both, so I_g R = V − I_g G ⇒ R = V/I_g − G. 4. R is large because V/I_g ≫ G typically. _Source: syllabus Physics Ch 3 §3.10 Galvanometer → Voltmeter_

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