ACSEE (Form 6) Mechanics (Projectile Motion) — practice questions

Explore 4 free Mechanics (Projectile Motion) questions in ACSEE (Form 6) Physics. Open each question or exercise to read its content, reference answers and available explanation.

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Mechanics (Projectile Motion) questions and exercises with answers

Showing questions 1–4 of 4.

A package is released from an aircraft flying level. Its time of fall is found from:Read the answer and worked solution →The speed of the falling package as it reaches the ground is found from:Read the answer and worked solution →Scale the projectile rangeRead the answer and worked solution →Complete the horizontal projectionRead the answer and worked solution →

Worked practice questions

A package is released from an aircraft flying level. Its time of fall is found from:

$t=\sqrt{\dfrac{2y}{g}}$
$t=\dfrac{v_0\sin\theta}{g}$
$t=\dfrac{2v_0}{g}$
$t=\dfrac{y}{v_0}$

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Correct answer: A. $t=\sqrt{\dfrac{2y}{g}}$

1. Released from level flight, the package starts with zero vertical velocity, so $\theta=0$. 2. The vertical equation $y=v_0\sin\theta\,t+\tfrac12 gt^2$ therefore reduces to $y=\tfrac12 gt^2$. 3. Rearranging for $t$ gives $t=\sqrt{\dfrac{2y}{g}}$. 4. The formula $t=\dfrac{v_0\sin\theta}{g}$ applies to a projectile launched at an angle, and here it evaluates to zero. 5. Missing that a horizontal projection has $\theta=0$ was the recorded error on this question. _Source: NECTA ACSEE 2023 Physics 131/1, Question 2: Mechanics (Projectile Motion)_

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The speed of the falling package as it reaches the ground is found from:

$V=\sqrt{V_x^2-V_y^2}$
$V=\sqrt{V_x^2+V_y^2}$
$V=\sqrt{V_x^2V_y^2}$
$V=\sqrt{V_x^2/V_y^2}$

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Correct answer: B. $V=\sqrt{V_x^2+V_y^2}$

1. The velocity has a horizontal component $V_x=v_0\cos\theta$, unchanged throughout the flight. 2. It also has a vertical component $V_y=v_0\sin\theta-gt$, which grows as the package falls. 3. These two components are perpendicular to one another. 4. The resultant of two perpendicular vectors is found by Pythagoras: $V=\sqrt{V_x^2+V_y^2}$. 5. Adding the components arithmetically ignores that they act at right angles and overstates the speed. _Source: NECTA ACSEE 2023 Physics 131/1, Question 2: Mechanics (Projectile Motion)_

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Scale the projectile range

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Questions

Hint
R is proportional to v squared
Answer
4
Question
Launch speed doubled. Range multiplies by?
Hint
same square relation
Answer
9
Question
Launch speed trebled. Range multiplies by?
Hint
one half squared
Answer
0.25
Question
Launch speed halved. Range multiplies by?

Instructions

Range varies as the square of the launch speed. Key in the factor.

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