alleryIntegral ∫ 1/sqrt(1 - x²) dx =
Aln(x)
Barctan(x)
Carcsin(x) + C
Darccos(x)
Answer & Solution
Correct answer: C. arcsin(x) + C
∫ dx/sqrt(1-x²) = arcsin(x) + C. (Or -arccos(x) + C', differs by constant.) Standard integral.
Keep practising Inverse Trigonometric Functions
Browse all Inverse Trigonometric Functions questions for AP Intermediate 2nd Year, or explore more Mathematics topics.
Related questions
All real $x$ satisfying $ in^{-1}(x) + in^{-1}(1-x) = \cos^{-1}(x)$ areFor $x = -2$, the value of $\tan^{-1}\left(\dfrac{2x}{1-x^2}\right)$ equals$\displaystyle um_{n=1}^{\infty} \tan^{-1}\left(\frac{1}{n^2 + n + 1}\right)$ equals$\tan^{-1}(1) + \tan^{-1}(2) + \tan^{-1}(3) = $$\cos^{-1}\left(\cos\tfrac{7\pi}{6}\right)$ equals$ in^{-1}\left( in\tfrac{2\pi}{3}\right)$ equals$\cot^{-1}\left(-\tfrac{1}{ qrt{3}}\right) = $$\tan^{-1}\left(\tfrac{1}{2}\right) + \tan^{-1}\left(\tfrac{1}{3}\right)$ equals