Home › CBSE Class 12 › Mathematics › Inverse Trigonometric Functions › The principal value of $\sin^{-1}(1/2)$ is:
The principal value of $\sin^{-1}(1/2)$ is:
A$\pi/3$, the angle whose sine is $\sqrt 3/2$ on chart
B$\pi/4$, the angle whose sine is $1/\sqrt 2$ on chart
C$\pi/6$, since $\sin(\pi/6) = 1/2$ in the principal range
D$\pi/2$, the angle whose sine is $1$ on the school chart
Answer & Solution
Correct answer: C. $\pi/6$, since $\sin(\pi/6) = 1/2$ in the principal range
$\sin(\pi/6) = 1/2$ and $\pi/6 \in [-\pi/2, \pi/2]$.
Related questions
The value of $ in(\tan^{-1}(3/4))$ is:The value of $\cos^{-1}(-1)$ is:For $x \in [-1, 1]$, the identity $ in^{-1}x + \cos^{-1}x$ equals:All real $x$ satisfying $ in^{-1}(x) + in^{-1}(1-x) = \cos^{-1}(x)$ areFor $x = -2$, the value of $\tan^{-1}\left(\dfrac{2x}{1-x^2}\right)$ equals$\displaystyle um_{n=1}^{\infty} \tan^{-1}\left(\frac{1}{n^2 + n + 1}\right)$ equals$\tan^{-1}(1) + \tan^{-1}(2) + \tan^{-1}(3) = $$\cos^{-1}\left(\cos\tfrac{7\pi}{6}\right)$ equals