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arctan(x) + arctan(1/x) (for x > 0) =

Aπ
B0
CDepends on x
Dπ/2
Answer & Solution
Correct answer: D. π/2
For x > 0: tan⁻¹(x) + tan⁻¹(1/x) = π/2. For x < 0: -π/2. Cotangent of arctan(x) is 1/x, so the two angles are complementary.
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