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Linear independence: two solutions y₁, y₂ of 2nd-order linear DE are independent iff Wronskian W:
AW = y₁ y₂' - y₂ y₁' ≠ 0
By₁ + y₂ = 0
CW = 0
DAlways 0
Answer & Solution
Correct answer: A. W = y₁ y₂' - y₂ y₁' ≠ 0
Wronskian W(y₁, y₂) = y₁ y₂' - y₂ y₁' ≠ 0 indicates linear independence. General solution of 2nd-order linear DE = c₁ y₁ + c₂ y₂ if y₁, y₂ linearly independent.
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