alleryInitial value problem: dy/dx = e^x with y(0) = 2. Solution:
Ay = 2e^x
By = e^x + 1 (since y(0) = 1 + 1 = 2)
Cy = e^x + 2
Dy = e^x
Answer & Solution
Correct answer: B. y = e^x + 1 (since y(0) = 1 + 1 = 2)
y = ∫e^x dx = e^x + C. y(0) = 1 + C = 2 → C = 1. So y = e^x + 1.
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