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Linear DE of first order: dy/dx + P(x) y = Q(x). Solution uses:
ATrial and error
BSubstitution
CDirect integration
DIntegrating factor μ = e^(∫P dx) and y × μ = ∫(Q × μ) dx + C
Answer & Solution
Correct answer: D. Integrating factor μ = e^(∫P dx) and y × μ = ∫(Q × μ) dx + C
Standard linear DE: multiply both sides by μ = e^(∫P dx). Then d/dx(μ y) = μ Q. Integrate: μy = ∫μQ dx + C → y = (1/μ)[∫μQ dx + C].
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