Home › JEE Advanced › Mathematics › Matrices and Determinants › For 2×2 matrix A = [[2,3],[1,4]], A⁻¹ =
For 2×2 matrix A = [[2,3],[1,4]], A⁻¹ =
A[[1/2,1/3],[1,1/4]]
BI
C(1/|A|) × [[4,-3],[-1,2]] = (1/5)[[4,-3],[-1,2]]
DSame as A
Answer & Solution
Correct answer: C. (1/|A|) × [[4,-3],[-1,2]] = (1/5)[[4,-3],[-1,2]]
|A| = 8 - 3 = 5. A⁻¹ = (1/|A|) × adj(A). For 2×2 [[a,b],[c,d]]: adj = [[d,-b],[-c,a]]. So A⁻¹ = (1/5)[[4,-3],[-1,2]].
Related questions
The topic that classifies row, column and square matrices is about the:Symmetric and skew symmetric matrices are both required to be:Every diagonal element of a skew symmetric matrix is:A square matrix whose transpose equals its negative is called:A square matrix equal to its own transpose is called:The properties of transpose are stated in the text:The transpose of matrix A is denoted by A with a prime or by A raised to:Interchanging the rows and columns of a matrix gives its: