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The product of a matrix $A$ of order $2\times 3$ and $B$ of order $3\times 4$ has order:
A$3\times 3$, taking the common dimension only here
B$2\times 4$, since outer dimensions give product order
C$2\times 3$, equal to the order of $A$ here in product
D$4\times 3$, the transposed result without doing AB
Answer & Solution
Correct answer: B. $2\times 4$, since outer dimensions give product order
$AB$ has order $m\times n = 2\times 4$, the outer dimensions.
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