alleryRadius of n-th Bohr orbit for hydrogen (a₀ ≈ 0.529 Å):
Aa₀
Ba₀ × n² (proportional to n²)
Ca₀ / n
Da₀ × n
Answer & Solution
Correct answer: B. a₀ × n² (proportional to n²)
r_n = n² × a₀ where a₀ ≈ 0.529 Å is Bohr radius.
So orbit 2 is 4× larger than orbit 1; orbit 3 is 9× larger.
Higher n gives much larger atoms (Rydberg states).
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