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With P(A) = 0.44, P(B) = 0.46 and P(A and B) = 0.16, the probability that neither A nor B occurs is:
A0.36 of trials
B0.26 of trials
C0.16 of trials
D0.10 of trials
Answer & Solution
Correct answer: B. 0.26 of trials
1. First find P(A or B) = 0.44 + 0.46 - 0.16 = 0.74.
2. Neither event means the complement of A-or-B.
3. P(neither) = 1 - 0.74 = 0.26.
_Source: NCERT Class 11 Mathematics, Ch 14 'Probability' (kemh114)_
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