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A fair coin is tossed three times. The probability of getting exactly two heads is:

A1/8 of trials
B1/2 of trials
C3/8 of trials
D1/4 of trials
Answer & Solution
Correct answer: C. 3/8 of trials
1. The 8 outcomes are equally likely. 2. Exactly two heads occurs as HHT, HTH and THH: 3 outcomes. 3. P(exactly two heads) = 3/8. _Source: syllabus Mathematics, Ch 14 'Probability' (kemh114)_
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