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Two dice are thrown. The probability that the sum of the numbers is at most 4 is:
A1/9 of throws
B1/6 of throws
C5/36 of throws
D1/12 of throws
Answer & Solution
Correct answer: B. 1/6 of throws
1. Sum 2: (1,1). Sum 3: (1,2), (2,1). Sum 4: (1,3), (2,2), (3,1).
2. Favourable outcomes: 1 + 2 + 3 = 6 out of 36.
3. P(sum at most 4) = 6/36 = 1/6.
_Source: NCERT Class 11 Mathematics, Ch 14 'Probability' (kemh114)_
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