alleryA and B are mutually exclusive with P(A) = 1/4 and P(B) = 1/3. The probability that A or B occurs is:
A7/12 of the trials
B1/12 of the trials
C5/12 of the trials
D1/7 of the trials
Answer & Solution
Correct answer: A. 7/12 of the trials
1. Mutually exclusive events cannot occur together, so P(A and B) = 0.
2. The addition rule reduces to P(A or B) = P(A) + P(B).
3. P = 1/4 + 1/3 = 3/12 + 4/12 = 7/12.
_Source: syllabus Mathematics, Ch 14 'Probability' (kemh114)_
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