Start learning →

If a wire of resistance R is stretched to twice its length (volume conserved), its new resistance becomes:

A4R
BR/2
C2R
DR/4
Answer & Solution
Correct answer: A. 4R
l → 2l, A → A/2 ⇒ R' = ρ(2l)/(A/2) = 4R.
Practise this question with Quill — NEET UG →

Keep practising Current Electricity

Browse all Current Electricity questions for NEET UG, or explore more Physics topics.

Start a Current Electricity lesson →