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For a business trip, Priya packs 3 skirts and 5 blouses, and each day decides whether or not to add her one sweater. How many different outfits of one skirt, one blouse, and a sweater choice are possible?
A15 outfits
B16 outfits
C30 outfits
D45 outfits
Answer & Solution
Correct answer: C. 30 outfits
1. The Multiplication Principle multiplies the number of options for each independent choice.
2. There are 3 skirt options, 5 blouse options, and 2 sweater options, wear it or not.
3. Multiply: 3 x 5 x 2 = 30 possible outfits.
4. Option A, 15, forgets that skipping the sweater and wearing it are two different outfits.
_Source: OpenStax Algebra and Trigonometry (CC BY 4.0), Ch 13 "Sequences, Probability and Counting Theory", section 13.5 COUNTING PRINCIPLES_
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