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In a double-slit experiment, if the wavelength is doubled and the slit separation is halved, the fringe width becomes

A{'text': '1/4 of original', 'label': 'A'}
B{'text': '4 times original', 'label': 'B'}
C{'text': '2 times original', 'label': 'C'}
D{'text': 'Same as original', 'label': 'D'}
Answer & Solution
Correct answer: B. {'text': '4 times original', 'label': 'B'}
1. β = λD/d. New wavelength = 2λ; new slit separation = d/2. 2. New β = (2λ)D / (d/2) = 4 × (λD/d) = 4β. 3. So the fringe width becomes 4 times the original. 4. Screen distance D was kept unchanged. _Source: NCERT Class 12 Physics, Ch 10 "Wave Optics", §10.4_
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