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HomeNEET UGphysicsWaves & Oscillations › Two waves y₁ = A sin(kx − ωt) and y₂ = A sin(kx …

Two waves y₁ = A sin(kx − ωt) and y₂ = A sin(kx − ωt + φ) superpose. The resulting amplitude is

A{'text': 'A + A × φ', 'label': 'A'}
B{'text': '2A × sin(φ/2)', 'label': 'B'}
C{'text': 'A × cos(φ)', 'label': 'C'}
D{'text': '2A × cos(φ/2)', 'label': 'D'}
Answer & Solution
Correct answer: D. {'text': '2A × cos(φ/2)', 'label': 'D'}
1. Superposition of two same-frequency waves with phase difference φ yields a resultant of the same frequency. 2. Amplitude of the resultant: A_res = 2 A cos(φ/2). 3. For φ = 0, constructive interference gives 2A; for φ = π destructive gives 0. 4. This is the basis of Young's double-slit interference. _Source: NCERT Class 11 Physics, Ch 14 "Waves", §14.5_
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