Home › JEE Advanced › Physics › Waves & Oscillations › The speed of sound in a gas is v = √(γP/ρ). This…
The speed of sound in a gas is v = √(γP/ρ). This is the
A{'text': 'Newton formula assuming isothermal propagation', 'label': 'A'}
B{'text': 'Doppler formula for observed frequency shifts', 'label': 'B'}
C{'text': 'Laplace-corrected Newton formula for adiabatic', 'label': 'C'}
D{'text': 'Bernoulli formula for fluid dynamics streamlines', 'label': 'D'}
Answer & Solution
Correct answer: C. {'text': 'Laplace-corrected Newton formula for adiabatic', 'label': 'C'}
1. Newton assumed sound propagates isothermally, giving v = √(P/ρ) — too low.
2. Laplace corrected: sound propagation is adiabatic, so v = √(γP/ρ).
3. γ = C_p / C_v is the ratio of specific heats.
4. This agrees with experimental values for air (v ≈ 340 m/s at STP).
_Source: NCERT Class 11 Physics, Ch 14 "Waves", §14.4_
Related questions
Frequency is one of the concepts used to describe motion that is:The letter used for the length of the pendulum string is:The letter used for the mass of the pendulum bob is:Any material medium can be pictured as a collection of:Besides free oscillations, the topic also treats oscillations that are damped and:Because the string is massless, the pendulum's moment of inertia comes from the:The free end of the pendulum string is fixed to a support that is:The string of a simple pendulum is also assumed to be: