The internal energy of 2 moles of nitrogen gas (rigid diatomic) at 300 K is approximately ($R = 8.314$):
A~ 1247 J
B~ 6240 J
C~ 12480 J
D~ 25000 J
Answer & Solution
Correct answer: C. ~ 12480 J
U = $n \cdot (5/2)RT = 2 \cdot (5/2)(8.314)(300) = 5 \cdot 8.314 \cdot 300 \cdot 2 / 2 = 12471$ J ≈ 12480 J.
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