alleryThe number of moles of oxygen ($O_2$) gas in a vessel of volume 1 L at STP (273.15 K, 1.013 × 10⁵ Pa) is approximately:
A~ 0.045 mol
B~ 0.045 g
C~ 1.0 mol
D~ 22.4 mol
Answer & Solution
Correct answer: A. ~ 0.045 mol
$n = PV/(RT) = (1.013\times10^5)(10^{-3})/(8.314\times273.15) = 101.3/2270.6 \approx 0.0446$ mol.
Equivalently, 22.4 L = 1 mol at STP, so 1 L ≈ 1/22.4 = 0.0446 mol.
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