For a **rigid diatomic** ideal gas, $\gamma = C_P/C_V$ equals:
A5/3 ≈ 1.67
B7/5 = 1.4
C9/7 ≈ 1.29
D4/3 ≈ 1.33
Answer & Solution
Correct answer: B. 7/5 = 1.4
Rigid diatomic: 5 DOF. $C_V = (5/2)R, C_P = (7/2)R$ ⇒ $\gamma = 7/5 = 1.4$. (Standard value used in air-related adiabatic calculations.)
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