The pressure of an ideal gas in kinetic theory is given by:
A$P = \frac{1}{3} \frac{N}{V} m \overline{v^2}$
B$P = \frac{1}{2} \frac{N}{V} m \overline{v^2}$
C$P = nRT$ only
D$P = N m v$
Answer & Solution
Correct answer: A. $P = \frac{1}{3} \frac{N}{V} m \overline{v^2}$
$P = (1/3)(N/V) m \langle v^2 \rangle$. Derived from molecular collisions with container walls: each molecule transfers momentum $2 m v_x$ per collision; averaging gives the factor 1/3.
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