If a, b and c are the zeros of the cubic polynomial 2x^3 - x^2 - 2x + 1, find the value of ab + bc + ca.
A2
B-1
C0
D+1
Answer & Solution
Correct answer: B. -1
1. For ax^3 + bx^2 + cx + d, the sum of products of zeros taken two at a time = c/a.
2. Here c = -2 and a = 2.
3. So ab + bc + ca = -2 / 2 = -1.
_Source: RRB Group D CEN-02/2018 PYQ, Q.84._
Related questions
Given any polynomial p(x) and any number a, which polynomial is always a factor of p(x) − Which of the following second-degree polynomials cannot be factored into first-degree realThe factorization of 2x² − 7x + 6 into first-degree polynomials is:In the polynomial x² + kx + 6, the value of k that makes x − 1 a factor is:The polynomial x² + 1 has no first-degree factors over the real numbers because:Using the quadratic formula, the solutions of x² − 30x + 221 = 0 are:Which first-degree polynomial is a factor of x⁵ − a⁵ for every value of a?If p(x) is a polynomial and p(a) = 0 for some number a, then which first-degree polynomial