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The factorization of 2x² − 7x + 6 into first-degree polynomials is:
A(x − 2)(2x − 3)
B(x + 2)(2x − 3)
C(x − 2)(2x + 3)
D(2x − 1)(x − 6)
Answer & Solution
Correct answer: A. (x − 2)(2x − 3)
1. Solve 2x² − 7x + 6 = 0: discriminant = 49 − 48 = 1.
2. x = (7 ± 1)/4 = 2 or 3/2.
3. Factors are x − 2 and x − 3/2.
4. Adjusting for leading coefficient 2: 2x² − 7x + 6 = 2(x − 2)(x − 3/2) = (x − 2)(2x − 3).
5. So the factorization is (x − 2)(2x − 3).
_Source: SCERT Kerala Std X Mathematics Part-2, Chapter 9-11 (pp 227-246, 2019 ed.)._
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