Which first-degree polynomial is a factor of x⁵ − a⁵ for every value of a?
Ax − a
Bx² − a²
Cx + a
Dx − a²
Answer & Solution
Correct answer: A. x − a
1. The unit's 'Power difference' box states that x − a is a factor of xⁿ − aⁿ for every natural number n.
2. For n = 5 the result xⁿ − aⁿ = x⁵ − a⁵.
3. So x − a is the first-degree factor.
4. The general formula gives x⁵ − a⁵ = (x − a)(x⁴ + ax³ + a²x² + a³x + a⁴).
5. The other options are higher-degree or wrong-sign factors.
_Source: SCERT Kerala Std X Mathematics Part-2, Chapter 9-11 (pp 227-246, 2019 ed.)._
Keep practising Real Numbers and Polynomials
Browse all Real Numbers and Polynomials questions for Kerala SSLC (Class 10), or explore more Mathematics topics.
Related questions
Fill the polynomial-factor blanks so each equation is true.Tap TRUE or FALSE for each polynomial / equation statement.Match each second-degree polynomial to its first-degree factorization.Given any polynomial p(x) and any number a, which polynomial is always a factor of p(x) − Which of the following second-degree polynomials cannot be factored into first-degree realThe factorization of 2x² − 7x + 6 into first-degree polynomials is:In the polynomial x² + kx + 6, the value of k that makes x − 1 a factor is:The polynomial x² + 1 has no first-degree factors over the real numbers because: