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A pair of dice is thrown 4 times. 'Getting a doublet' is a success. The probability of **exactly 2 successes** is:
A$25/216$
B$25/216$
C$6 \cdot (1/6)^2 \cdot (5/6)^2 = 150/1296 \approx 0.116$
DCannot be determined
Answer & Solution
Correct answer: C. $6 \cdot (1/6)^2 \cdot (5/6)^2 = 150/1296 \approx 0.116$
Doublet probability $p = 6/36 = 1/6$. $n = 4$. $P(X = 2) = {}^4C_2 (1/6)^2 (5/6)^2 = 6 \cdot (1/36)(25/36) = 150/1296 = 25/216 \approx 0.116$.
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