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If $X \sim B(4, p)$ and $P(X = 0) = 16/81$, then $P(X = 4)$ equals:
A$1/16$
B$1/81$
C$1/27$
D$1/8$
Answer & Solution
Correct answer: B. $1/81$
$P(X = 0) = q^4 = 16/81$ ⇒ $q = 2/3$ ⇒ $p = 1/3$. $P(X = 4) = p^4 = (1/3)^4 = 1/81$.
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