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The probability that a shooter hits a target is 3/4. The minimum number of shots required so that the probability of **hitting at least once** is more than 0.99 is:
A2
B3
C4 (approx — solve $(1/4)^n < 0.01$)
D5
Answer & Solution
Correct answer: C. 4 (approx — solve $(1/4)^n < 0.01$)
$1 - (1/4)^n > 0.99$ ⇒ $(1/4)^n < 0.01$. For $n=3$: $(1/4)^3 = 1/64 \approx 0.0156$ (too big). For $n=4$: $1/256 \approx 0.0039 < 0.01$ ✓.
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