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For a Binomial distribution $X \sim B(n, p)$, the **variance** is:
A$np$
B$npq$ where $q = 1 - p$
C$\sqrt{np}$
D$n^2 p^2$
Answer & Solution
Correct answer: B. $npq$ where $q = 1 - p$
Var$(X) = npq$. Note: variance ≤ mean for binomial (since $q \le 1$), with equality only when $p = 0$.
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