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The LUCAS REAGENT is used to distinguish between primary, secondary, and tertiary alcohols. It consists of
Aconcentrated $\mathrm{H_2SO_4}$ + $\mathrm{KMnO_4}$
BPCC + dichloromethane
Cconcentrated HCl + anhydrous $\mathrm{ZnCl_2}$
DNaOH + ethanol
Answer & Solution
Correct answer: C. concentrated HCl + anhydrous $\mathrm{ZnCl_2}$
1. NCERT §7.4 describes the Lucas test.
2. REAGENT: concentrated HCl + anhydrous $\mathrm{ZnCl_2}$ (the Lucas reagent).
3. The test distinguishes alcohols by RATE of formation of alkyl chloride (which appears as TURBIDITY since alkyl chlorides are insoluble in the aqueous reagent).
4. Results:
• 3° alcohol: turbidity APPEARS IMMEDIATELY (carbocation forms easily — tertiary carbocations very stable).
• 2° alcohol: turbidity in ~5–10 minutes.
• 1° alcohol: NO turbidity at room temperature (would need heat).
5. Option B is an oxidising mix (could oxidise alcohols, different test). Options C and D are unrelated chemistry.
_Source: NCERT Class 12 Chemistry Part 2, Ch 7, §7.4 (Distinction of 1°, 2°, 3° alcohols — Lucas test), p. 11._
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