A radioactive sample decays following $dN/dt = -\lambda N$. The amount…

Question

A radioactive sample decays following $dN/dt = -\lambda N$. The amount $N(t)$ as a function of time is:

Accepted Answer

D. $N_0 e^{-\lambda t}$, the exponential decay solution on the chart

Solving $dN/dt = -\lambda N$ gives $N = N_0 e^{-\lambda t}$.

Answer

$N_0\sin(\lambda t)$, the sinusoidal form on chart here

Answer

$N_0(1 - e^{-\lambda t})$, the saturation form on chart here

Answer

$N_0(1 + \lambda t)$, the linear approximation on the chart