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A radioactive sample decays following $dN/dt = -\lambda N$. The amount $N(t)$ as a function of time is:
A$N_0\sin(\lambda t)$, the sinusoidal form on chart here
B$N_0(1 - e^{-\lambda t})$, the saturation form on chart here
C$N_0(1 + \lambda t)$, the linear approximation on the chart
D$N_0 e^{-\lambda t}$, the exponential decay solution on the chart
Answer & Solution
Correct answer: D. $N_0 e^{-\lambda t}$, the exponential decay solution on the chart
Solving $dN/dt = -\lambda N$ gives $N = N_0 e^{-\lambda t}$.
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