Home › GUJCET › Chemistry › Electrochemical Series › The molar conductivities of HCl, CH₃COONa, and N…
The molar conductivities of HCl, CH₃COONa, and NaCl at infinite dilution are 426.1, 91.0 and 126.4 Ω⁻¹ cm² mol⁻¹ respectively. The molar conductivity of CH₃COOH at infinite dilution is:
A61.3 Ω⁻¹ cm² mol⁻¹
B552.5 Ω⁻¹ cm² mol⁻¹
C390.7 Ω⁻¹ cm² mol⁻¹
D200.5 Ω⁻¹ cm² mol⁻¹
Answer & Solution
Correct answer: C. 390.7 Ω⁻¹ cm² mol⁻¹
$\Lambda_0$(CH₃COOH) = $\Lambda_0$(HCl) + $\Lambda_0$(CH₃COONa) − $\Lambda_0$(NaCl) = 426.1 + 91.0 − 126.4 = **390.7** Ω⁻¹ cm² mol⁻¹. Standard Kohlrausch construction for a weak acid.
Related questions
The electrolytes of the two half-cells are joined by a:The two portions of a galvanic cell are also called:In the Daniell cell, zinc dissolves at the anode and copper:A negative standard potential marks a reducing agent that is:Going from top to bottom of the table, the electrode potential:The weakest oxidising agent in the table of potentials is:The most powerful reducing agent in aqueous solution is:The weakest reducing agent in the table of potentials is: